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skipping modifiers


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rollerpigeon1963
76 posts
Apr 01, 2006
8:08 AM
I have a question that has bothered me for a while. As you all know that grizzle is a dominate modifier. So here is my quetion? If you bred a red check to a red check grizzle. Will all the squeekers be grizzle? Because I remember I had this same example in my loft a few years ago. And a friend of mine just brought it up because he had the same outcome. I had a red check cock and a red grizzle hen. And they had 2 squeekers one was a red grizzle cock and the other was a self check hen. And the red self hen didn't produce a grizzle for the first 3 rounds. How is this possible? The original breeders were bred in individual breeding cages. And they had 2 others rounds before having this round that I'm talking about. So what I'm asking is it possible for a modifier to skip a squeeker?
Thanks Brian

Last Edited by rollerpigeon1963 on Apr 01, 2006 8:09 AM
MCCORMICKLOFTS
457 posts
Apr 01, 2006
4:13 PM
Brian, there are several kinds of grizzle, but they are dominants and all work the same way. In such a mating you described, (grizzle x non grizzle) you can expect to produce 50 percent of each. Now you might get six grizzles in the first three rounds, then two non grizzles in the next. If you stopped there, you would have 75 percent grizzles as opposed to non. But the law of averages is based over a period of time. If you were to breed that pair and produce 25-50 offspring, chances are it would be right on 50/50.
If you use a bird that is homozygous grizzle, then yes, all of it's offspring will be grizzle.
If you mate two het grizzles together, 25 percent will be homozygous, 50 percent will be het (regular grizzle, one dose) and 25 percent will be non grizzles. Yes you can raise a non grizzle from two grizzles, but it won't be many.
Brian (the other one...lol)

Last Edited by MCCORMICKLOFTS on Apr 01, 2006 4:14 PM


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